CU Amiga Super CD-ROM 17/CU Amiga Magazine's Super CD-ROM 17 (1997)(EMAP Images)(GB)[!][issue 1997-12].iso/CUCD/Programming/AMOSList/AMOSLIST.0897/[e-mail]_Wed Aug 6 23:11:43 1997.msg

Text File | 1997-09-09 | 3KB | 68 lines

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Date: Wed, 6 Aug 97 18:10:16 UT
From: "SYLVIA SANCHEZ" <[e-mail]>
Message-Id: <[e-mail]>
To: [e-mail]
Subject: OK FAST MEM NOT SOLVED
Status: O
X-Status:

Hi Sam Becket,

Well, you are right.  The program by Neil Kennedy was just a demo program.  He
stated at the beginning of the listing that he needed a program to see if a
computer was more than a 1 meg machine.  I suppose this type of program
depends on what you wish to accomplish.  However, I do think it is an
important question, as it pretty much relates to my question about doing
without double buffer in order to save available memory.

Anyway, I tested FAST FREE on a 1 meg machine.  Apparently, I discovered that
my 1.3 OS used 153,288 K of memory leaving 895,288 free memory.  After loading
AMOS PRO, there was 392,560 free memory.  I guess AMOS PRO uses 502,965 K of
which lets say 25,000 K is reserved for text (out of FAST RAM).  The more text
space reserved the less FAST FREE.

For a compiled program, AMOS sys & libs consumes around 80 K of disk space, so
I suppose there would be even more FAST RAM left.  At this point, I have no
idea how large your program is going to be.  I suppose that 8 disks could
potentially consume 8 MB of ram.

Anyway, getting back to the 1 meg machine.  There was 0 or zero FAST MEM and
402,704 for CHIP MEM.  As far as I can tell, there is no FAST MEM on a 1 meg
machine as far as AMOS is concerned.  Therefore,

If FAST FREE = 0, then load only one disk program.

My system is actually a 3 meg machine, however after loading the OS & AMOS, it
has only 2,333,048 FREE MEM left.  Apparently my system uses 812,680 which
probably includes OS and peripherals.  When I test CHIP FREE the amount was
increased from 402,704 to 813,680 out of the total FREE MEM available!  I
figured that CHIP FREE was just using all available memory for a 1 meg machine
which would be about 813,680 + 153,288 for the OS.  Anyway that is my guess.
Anyway, on my system, I figure that I could load potentially a 2 disk program
(maybe 3).

If FAST FREE <= 700,000 then load 1 disk
if FAST FREE > 700,000 and <= 1,400,000 then load 2 disks
if FAST FREE >1,400,000 <= 2,100,000 then load 3 disks

Does anyone have a better way to do this?  Damn, I just realized that this
does have to be done in the startup sequence, before loading the AMOS
program!!  I think I having doing this all back-arse-wards!  Am I wrong here?

Rudy
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